What are the solutions to the equation 9x^2-6x+145=0 ?

The solutions to the equation 9x^2-6x+145=0 are x= 1/3+4i,x= 1/3-4i

Find the zeros of 9x^2-6x+145=0

The zeros of 9x^2-6x+145=0 are x= 1/3+4i,x= 1/3-4i

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9 x^{2} - 6 x + 145 = 0

x = \frac{1}{3} + 4 i, x = \frac{1}{3} - 4 i

Solution steps

9 x^{2} - 6 x + 145 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 145}{2 \cdot 9}

Simplify

(- 6)^{2} - 4 \cdot 9 \cdot 145 : 72 i

x_{1, 2} = \frac{- ( - 6 ) \pm 72 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 72 i}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 72 i}{2 \cdot 9}

x = \frac{- ( - 6 ) + 72 i}{2 \cdot 9} : \frac{1}{3} + 4 i

x = \frac{- ( - 6 ) - 72 i}{2 \cdot 9} : \frac{1}{3} - 4 i

The solutions to the quadratic equation are:

x = \frac{1}{3} + 4 i, x = \frac{1}{3} - 4 i

∣ 3 x - 1 ∣ < - 5

a^{2} - 9 b^{2}

100 y^{2} - 121 z^{4}

- 3 (- 8) + 2 (- 4) = 5

\frac{4 !}{( 4 - 4 ) ! 4 !}

What are the solutions to the equation 9x^2-6x+145=0 ?
The solutions to the equation 9x^2-6x+145=0 are x= 1/3+4i,x= 1/3-4i
Find the zeros of 9x^2-6x+145=0
The zeros of 9x^2-6x+145=0 are x= 1/3+4i,x= 1/3-4i