What are the solutions to the equation 4x^2-9x-28=0 ?

The solutions to the equation 4x^2-9x-28=0 are x=4,x=-7/4

Find the zeros of 4x^2-9x-28=0

The zeros of 4x^2-9x-28=0 are x=4,x=-7/4

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4 x^{2} - 9 x - 28 = 0

x = 4, x = - \frac{7}{4}

Solution steps

4 x^{2} - 9 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 ( - 28 )}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 (- 28) = 23

x_{1, 2} = \frac{- ( - 9 ) \pm 23}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 23}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 23}{2 \cdot 4}

x = \frac{- ( - 9 ) + 23}{2 \cdot 4} : 4

x = \frac{- ( - 9 ) - 23}{2 \cdot 4} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = 4, x = - \frac{7}{4}

(15 - 3)^{2}

2 p + 2 < 6

169 = 275 - u

∣ 4 + 2 x ∣ = ∣ 5 - x ∣

18 + 7 n + 3 + 6 n \leq 86

What are the solutions to the equation 4x^2-9x-28=0 ?
The solutions to the equation 4x^2-9x-28=0 are x=4,x=-7/4
Find the zeros of 4x^2-9x-28=0
The zeros of 4x^2-9x-28=0 are x=4,x=-7/4