What are the solutions to the equation 2b^2+5b-12=0 ?

The solutions to the equation 2b^2+5b-12=0 are b= 3/2 ,b=-4

Find the zeros of 2b^2+5b-12=0

The zeros of 2b^2+5b-12=0 are b= 3/2 ,b=-4

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2 b^{2} + 5 b - 12 = 0

b = \frac{3}{2}, b = - 4

Solution steps

2 b^{2} + 5 b - 12 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 12) = 11

b_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 2}

Separate the solutions

b_{1} = \frac{- 5 + 11}{2 \cdot 2}, b_{2} = \frac{- 5 - 11}{2 \cdot 2}

b = \frac{- 5 + 11}{2 \cdot 2} : \frac{3}{2}

b = \frac{- 5 - 11}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

b = \frac{3}{2}, b = - 4

3 x - \frac{2 x}{5} = \frac{3 x}{10} + 14

7 (x + 4) = 56

\frac{x ^{2} + 3 x - 10}{x ^{2} - 4}

9 m^{2} - 45 m + 18 m^{3}

(8 + 5 i) (6 + 3 i)

What are the solutions to the equation 2b^2+5b-12=0 ?
The solutions to the equation 2b^2+5b-12=0 are b= 3/2 ,b=-4
Find the zeros of 2b^2+5b-12=0
The zeros of 2b^2+5b-12=0 are b= 3/2 ,b=-4