What are the solutions to the equation x^2+17x+42=0 ?

The solutions to the equation x^2+17x+42=0 are x=-3,x=-14

Find the zeros of x^2+17x+42=0

The zeros of x^2+17x+42=0 are x=-3,x=-14

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x^{2} + 17 x + 42 = 0

x = - 3, x = - 14

Solution steps

x^{2} + 17 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 42}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 42 = 11

x_{1, 2} = \frac{- 17 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 11}{2 \cdot 1}, x_{2} = \frac{- 17 - 11}{2 \cdot 1}

x = \frac{- 17 + 11}{2 \cdot 1} : - 3

x = \frac{- 17 - 11}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = - 3, x = - 14

0.0625

4 x^{2} + 19 x + 12

\frac{3 x ^{4} y ^{7} z ^{3}}{x y ^{2} z ^{3}}

3 x^{2} - 20 x = 7

9 x^{2} + 15 x

What are the solutions to the equation x^2+17x+42=0 ?
The solutions to the equation x^2+17x+42=0 are x=-3,x=-14
Find the zeros of x^2+17x+42=0
The zeros of x^2+17x+42=0 are x=-3,x=-14