What is -3+sqrt(6x+1)>4 ?

The solution to -3+sqrt(6x+1)>4 is x>8

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-3+sqrt(6x+1)>4

- 3 + 6 x + 1 > 4

x > 8

Interval Notation

(8, \infty)

Solution steps

- 3 + 6 x + 1 > 4

Move

3

to the right side

6 x + 1 > 7

Square both sides

(6 x + 1)^{2} > 7^{2}

Simplify

6 x + 1 > 49

6 x + 1 > 49 : x > 8

x > 8

Find singularity points

Find non-negative values for radicals:

x \geq - \frac{1}{6}

Combine the intervals

x > 8 and x \geq - \frac{1}{6}

Merge Overlapping Intervals

x > 8

- 10 \leq 2 x - 4 < - 2

9^{3} \cdot 3^{2} \cdot \frac{3 ^{6}}{3 ^{7}}

5 (\frac{x}{5} - (\frac{x}{5} - (\frac{x}{5} + \frac{3 x}{5} - 80))) = 900

y^{2} - 12 y + 32 = 0

(z + 2)^{2} - 5 (z + 2)