What are the solutions to the equation 4x^2+35x+24=0 ?

The solutions to the equation 4x^2+35x+24=0 are x=-3/4 ,x=-8

Find the zeros of 4x^2+35x+24=0

The zeros of 4x^2+35x+24=0 are x=-3/4 ,x=-8

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4 x^{2} + 35 x + 24 = 0

x = - \frac{3}{4}, x = - 8

Solution steps

4 x^{2} + 35 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 \cdot 4 \cdot 24}{2 \cdot 4}

3 5^{2} - 4 \cdot 4 \cdot 24 = 29

x_{1, 2} = \frac{- 35 \pm 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 35 + 29}{2 \cdot 4}, x_{2} = \frac{- 35 - 29}{2 \cdot 4}

x = \frac{- 35 + 29}{2 \cdot 4} : - \frac{3}{4}

x = \frac{- 35 - 29}{2 \cdot 4} : - 8

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - 8

5 - 8 x < 2 x + 3

(7 x)^{3}

(\frac{3 ^{x} + 3 ^{- x}}{2})^{2}

2 x^{2} + 1 x - 1 = 0

- 6 = \frac{b}{18}

What are the solutions to the equation 4x^2+35x+24=0 ?
The solutions to the equation 4x^2+35x+24=0 are x=-3/4 ,x=-8
Find the zeros of 4x^2+35x+24=0
The zeros of 4x^2+35x+24=0 are x=-3/4 ,x=-8