What are the solutions to the equation k^2-5k=k+7 ?

The solutions to the equation k^2-5k=k+7 are k=7,k=-1

Find the zeros of k^2-5k=k+7

The zeros of k^2-5k=k+7 are k=7,k=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

k^{2} - 5 k = k + 7

k = 7, k = - 1

Solution steps

k^{2} - 5 k = k + 7

Move

7

to the left side

k^{2} - 5 k - 7 = k

Move

k

to the left side

k^{2} - 6 k - 7 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 7) = 8

k_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 6 ) + 8}{2 \cdot 1}, k_{2} = \frac{- ( - 6 ) - 8}{2 \cdot 1}

k = \frac{- ( - 6 ) + 8}{2 \cdot 1} : 7

k = \frac{- ( - 6 ) - 8}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

k = 7, k = - 1

6 x^{2} y - 28 x y + 30 y

14 = x 2

\frac{- 4 w ^{- 4} x ^{3}}{12 w ^{5} x ^{- \frac{1}{8}}}

\frac{1}{9} π

\frac{7 \cdot 1 0 ^{8}}{2 \cdot 1 0 ^{5}}

What are the solutions to the equation k^2-5k=k+7 ?
The solutions to the equation k^2-5k=k+7 are k=7,k=-1
Find the zeros of k^2-5k=k+7
The zeros of k^2-5k=k+7 are k=7,k=-1