What are the solutions to the equation 6x^2+9x=32 ?

The solutions to the equation 6x^2+9x=32 are x=(-9+sqrt(849))/(12),x=(-9-sqrt(849))/(12)

Find the zeros of 6x^2+9x=32

The zeros of 6x^2+9x=32 are x=(-9+sqrt(849))/(12),x=(-9-sqrt(849))/(12)

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6 x^{2} + 9 x = 32

x = \frac{- 9 + 849}{12}, x = \frac{- 9 - 849}{12}

Decimal Notation

x = 1.67813 \dots, x = - 3.17813 \dots

Solution steps

6 x^{2} + 9 x = 32

Move

32

to the left side

6 x^{2} + 9 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 ( - 32 )}{2 \cdot 6}

9^{2} - 4 \cdot 6 (- 32) = 849

x_{1, 2} = \frac{- 9 \pm 849}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 9 + 849}{2 \cdot 6}, x_{2} = \frac{- 9 - 849}{2 \cdot 6}

x = \frac{- 9 + 849}{2 \cdot 6} : \frac{- 9 + 849}{12}

x = \frac{- 9 - 849}{2 \cdot 6} : \frac{- 9 - 849}{12}

The solutions to the quadratic equation are:

x = \frac{- 9 + 849}{12}, x = \frac{- 9 - 849}{12}

x y + 2 x^{2}

3 x^{2} + 27 = 0

e^{0.2}

x^{2} - 3 x + 1 = 0

What are the solutions to the equation 6x^2+9x=32 ?
The solutions to the equation 6x^2+9x=32 are x=(-9+sqrt(849))/(12),x=(-9-sqrt(849))/(12)
Find the zeros of 6x^2+9x=32
The zeros of 6x^2+9x=32 are x=(-9+sqrt(849))/(12),x=(-9-sqrt(849))/(12)