What are the solutions to the equation 6x^2+4x+6=0 ?

The solutions to the equation 6x^2+4x+6=0 are x=-1/3+i(2sqrt(2))/3 ,x=-1/3-i(2sqrt(2))/3

Find the zeros of 6x^2+4x+6=0

The zeros of 6x^2+4x+6=0 are x=-1/3+i(2sqrt(2))/3 ,x=-1/3-i(2sqrt(2))/3

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6 x^{2} + 4 x + 6 = 0

x = - \frac{1}{3} + i \frac{2 2}{3}, x = - \frac{1}{3} - i \frac{2 2}{3}

Solution steps

6 x^{2} + 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

Simplify

4^{2} - 4 \cdot 6 \cdot 6 : 82 i

x_{1, 2} = \frac{- 4 \pm 8 2 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 4 + 8 2 i}{2 \cdot 6}, x_{2} = \frac{- 4 - 8 2 i}{2 \cdot 6}

x = \frac{- 4 + 8 2 i}{2 \cdot 6} : - \frac{1}{3} + i \frac{2 2}{3}

x = \frac{- 4 - 8 2 i}{2 \cdot 6} : - \frac{1}{3} - i \frac{2 2}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{2 2}{3}, x = - \frac{1}{3} - i \frac{2 2}{3}

32 + 18 r + r^{2}

ln (\frac{1}{3})

- \frac{1}{6} (200)^{2} + 100 (200)

(2 t)^{2}

3 x^{2} + 19 x + 28

What are the solutions to the equation 6x^2+4x+6=0 ?
The solutions to the equation 6x^2+4x+6=0 are x=-1/3+i(2sqrt(2))/3 ,x=-1/3-i(2sqrt(2))/3
Find the zeros of 6x^2+4x+6=0
The zeros of 6x^2+4x+6=0 are x=-1/3+i(2sqrt(2))/3 ,x=-1/3-i(2sqrt(2))/3