What are the solutions to the equation k^2+5k-6=0 ?

The solutions to the equation k^2+5k-6=0 are k=1,k=-6

Find the zeros of k^2+5k-6=0

The zeros of k^2+5k-6=0 are k=1,k=-6

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k^{2} + 5 k - 6 = 0

k = 1, k = - 6

Solution steps

k^{2} + 5 k - 6 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 6) = 7

k_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 5 + 7}{2 \cdot 1}, k_{2} = \frac{- 5 - 7}{2 \cdot 1}

k = \frac{- 5 + 7}{2 \cdot 1} : 1

k = \frac{- 5 - 7}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

k = 1, k = - 6

(2 x)^{2} 2 y

d^{2} - 6 d - 7

\frac{1}{2} - x + \frac{3}{2} = x - 4

6 x^{2} - 5 x - 21 = 0

\frac{3 n - 7}{6} = \frac{2 n + 5}{3}

What are the solutions to the equation k^2+5k-6=0 ?
The solutions to the equation k^2+5k-6=0 are k=1,k=-6
Find the zeros of k^2+5k-6=0
The zeros of k^2+5k-6=0 are k=1,k=-6