What are the solutions to the equation 2x^2+14x=0 ?

The solutions to the equation 2x^2+14x=0 are x=0,x=-7

Find the zeros of 2x^2+14x=0

The zeros of 2x^2+14x=0 are x=0,x=-7

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2 x^{2} + 14 x = 0

x = 0, x = - 7

Solution steps

2 x^{2} + 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

1 4^{2} - 4 \cdot 2 \cdot 0 = 14

x_{1, 2} = \frac{- 14 \pm 14}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 14 + 14}{2 \cdot 2}, x_{2} = \frac{- 14 - 14}{2 \cdot 2}

x = \frac{- 14 + 14}{2 \cdot 2} : 0

x = \frac{- 14 - 14}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

16 x \leq x^{3}

u + 1.8 = 8.26

\frac{x}{x ^{2}}

- 2 (\frac{1}{2})^{0}

\frac{- 2}{- i}

What are the solutions to the equation 2x^2+14x=0 ?
The solutions to the equation 2x^2+14x=0 are x=0,x=-7
Find the zeros of 2x^2+14x=0
The zeros of 2x^2+14x=0 are x=0,x=-7