What is (-8n+4)/(11n(n+1))*(4n^2)/(-10n+5) ?

The solution to (-8n+4)/(11n(n+1))*(4n^2)/(-10n+5) is (16n)/(55(n+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (-8n+4)/(11n(n+1))*(4n^2)/(-10n+5)

simplify

\frac{- 8 n + 4}{11 n ( n + 1 )} \cdot \frac{4 n ^{2}}{- 10 n + 5}

\frac{16 n}{55 ( n + 1 )}

Solution steps

\frac{- 8 n + 4}{11 n ( n + 1 )} \cdot \frac{4 n ^{2}}{- 10 n + 5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( - 8 n + 4 ) \cdot 4 n ^{2}}{11 n ( n + 1 ) ( - 10 n + 5 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

n^{2} = nn

= \frac{( - 8 n + 4 ) \cdot 4 nn}{11 n ( n + 1 ) ( - 10 n + 5 )}

Cancel the common factor:

n

= \frac{( - 8 n + 4 ) \cdot 4 n}{11 ( n + 1 ) ( - 10 n + 5 )}

Factor

- 8 n + 4 : 4 (- 2 n + 1)

= \frac{4 ( - 2 n + 1 ) \cdot 4 n}{11 ( n + 1 ) ( - 10 n + 5 )}

Factor

- 10 n + 5 : 5 (- 2 n + 1)

= \frac{4 ( - 2 n + 1 ) \cdot 4 n}{11 ( n + 1 ) \cdot 5 ( - 2 n + 1 )}

Cancel the common factor:

- 2 n + 1

= \frac{4 \cdot 4 n}{11 ( n + 1 ) \cdot 5}

Multiply the numbers:

4 \cdot 4 = 16

= \frac{16 n}{11 ( n + 1 ) \cdot 5}

Multiply the numbers:

11 \cdot 5 = 55

= \frac{16 n}{55 ( n + 1 )}

9 w^{2} + 9 w - 4

(- \frac{5}{6})^{2}

(- 49)^{\frac{1}{2}}

(\frac{6}{5})^{2}

5 x + 4 = 3 x + 6

What is (-8n+4)/(11n(n+1))*(4n^2)/(-10n+5) ?
The solution to (-8n+4)/(11n(n+1))*(4n^2)/(-10n+5) is (16n)/(55(n+1))