What is ((p^2r^3)/(pr^4))^2 ?

The solution to ((p^2r^3)/(pr^4))^2 is (p^2)/(r^2)

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simplify ((p^2r^3)/(pr^4))^2

simplify

(\frac{p ^{2} r ^{3}}{p r ^{4}})^{2}

\frac{p ^{2}}{r ^{2}}

Solution steps

(\frac{p ^{2} r ^{3}}{p r ^{4}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( p ^{2} r ^{3} ) ^{2}}{( p r ^{4} ) ^{2}}

Simplify

(p^{2} r^{3})^{2} : p^{4} r^{6}

= \frac{p ^{4} r ^{6}}{( p r ^{4} ) ^{2}}

Simplify

(p r^{4})^{2} : p^{2} r^{8}

= \frac{p ^{4} r ^{6}}{p ^{2} r ^{8}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{p ^{4}}{p ^{2}} = p^{4 - 2}

= \frac{p ^{4 - 2} r ^{6}}{r ^{8}}

Subtract the numbers:

4 - 2 = 2

= \frac{p ^{2} r ^{6}}{r ^{8}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{r ^{6}}{r ^{8}} = \frac{1}{r ^{8 - 6}}

= \frac{p ^{2}}{r ^{8 - 6}}

Subtract the numbers:

8 - 6 = 2

= \frac{p ^{2}}{r ^{2}}

x^{2} - 14 x + 22 = 0

\frac{p}{2} + 7 \leq 10

(x + 6) (2 x - 5) = 0

5 (3 d - 7) + 7 d = 10 d - (14 - 3 d)

2 x + 1 \leq 7

What is ((p^2r^3)/(pr^4))^2 ?
The solution to ((p^2r^3)/(pr^4))^2 is (p^2)/(r^2)