What are the solutions to the equation 7x-4x^2=0 ?

The solutions to the equation 7x-4x^2=0 are x=0,x= 7/4

Find the zeros of 7x-4x^2=0

The zeros of 7x-4x^2=0 are x=0,x= 7/4

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7 x - 4 x^{2} = 0

x = 0, x = \frac{7}{4}

Decimal Notation

x = 0, x = 1.75

Solution steps

7 x - 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

7^{2} - 4 (- 4) \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 ( - 4 )}, x_{2} = \frac{- 7 - 7}{2 ( - 4 )}

x = \frac{- 7 + 7}{2 ( - 4 )} : 0

x = \frac{- 7 - 7}{2 ( - 4 )} : \frac{7}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{7}{4}

4 x = 2

6 x^{2} + 17 x + 10

2 x^{2} - 5 x - 33

x^{2} \leq 42 - x

- 3 (- 10 x + 7) = 7 + 8 (\frac{3}{2} x - \frac{5}{2}) + 4 x

What are the solutions to the equation 7x-4x^2=0 ?
The solutions to the equation 7x-4x^2=0 are x=0,x= 7/4
Find the zeros of 7x-4x^2=0
The zeros of 7x-4x^2=0 are x=0,x= 7/4