What are the solutions to the equation (x-6)(x+4)=0 ?

The solutions to the equation (x-6)(x+4)=0 are x=6,x=-4

Find the zeros of (x-6)(x+4)=0

The zeros of (x-6)(x+4)=0 are x=6,x=-4

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(x - 6) (x + 4) = 0

x = 6, x = - 4

Solution steps

(x - 6) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x + 4 = 0

Solve

x - 6 = 0 : x = 6

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = 6, x = - 4

y^{2} - 2 y + 1

\frac{1}{1 2 ^{4}}

\frac{x - 2}{x + 3} \geq 0

\frac{ln ( 1 )}{2}

2 (x + 12) - 16 \leq 8

What are the solutions to the equation (x-6)(x+4)=0 ?
The solutions to the equation (x-6)(x+4)=0 are x=6,x=-4
Find the zeros of (x-6)(x+4)=0
The zeros of (x-6)(x+4)=0 are x=6,x=-4