What are the solutions to the equation (12x-27)^2=256 ?

The solutions to the equation (12x-27)^2=256 are x= 43/12 ,x= 11/12

Find the zeros of (12x-27)^2=256

The zeros of (12x-27)^2=256 are x= 43/12 ,x= 11/12

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(12 x - 27)^{2} = 256

x = \frac{43}{12}, x = \frac{11}{12}

Decimal Notation

x = 3.58333 \dots, x = 0.91666 \dots

Solution steps

(12 x - 27)^{2} = 256

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

12 x - 27 = 256 : x = \frac{43}{12}

Solve

12 x - 27 = - 256 : x = \frac{11}{12}

The solutions to the quadratic equation are:

x = \frac{43}{12}, x = \frac{11}{12}

\frac{6}{( x - 2 )} \leq x - 3

- 2 z + 10 + 7 z = 16 z + 7

5 x^{2} + 120 = - 50 x

- 3 = 4 x^{2} - x - 3

1 - 2 x \leq (x + 5)^{2} - 2 (x + 1)

What are the solutions to the equation (12x-27)^2=256 ?
The solutions to the equation (12x-27)^2=256 are x= 43/12 ,x= 11/12
Find the zeros of (12x-27)^2=256
The zeros of (12x-27)^2=256 are x= 43/12 ,x= 11/12