What are the solutions to the equation x^2-6x+16=0 ?

The solutions to the equation x^2-6x+16=0 are x=3+sqrt(7)i,x=3-sqrt(7)i

Find the zeros of x^2-6x+16=0

The zeros of x^2-6x+16=0 are x=3+sqrt(7)i,x=3-sqrt(7)i

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x^{2} - 6 x + 16 = 0

x = 3 + 7 i, x = 3 - 7 i

Solution steps

x^{2} - 6 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 16 : 27 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 1} : 3 + 7 i

x = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 1} : 3 - 7 i

The solutions to the quadratic equation are:

x = 3 + 7 i, x = 3 - 7 i

2 y^{2} + 10 y = - 11

16 x^{2} - 1 = 0

7 + 4 (2 a + 15) = - 13

∣ y ∣ > 6

a^{2} + ab

What are the solutions to the equation x^2-6x+16=0 ?
The solutions to the equation x^2-6x+16=0 are x=3+sqrt(7)i,x=3-sqrt(7)i
Find the zeros of x^2-6x+16=0
The zeros of x^2-6x+16=0 are x=3+sqrt(7)i,x=3-sqrt(7)i