What are the solutions to the equation -5x^2+9=9x+13 ?

The solutions to the equation -5x^2+9=9x+13 are x=-1,x=-4/5

Find the zeros of -5x^2+9=9x+13

The zeros of -5x^2+9=9x+13 are x=-1,x=-4/5

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- 5 x^{2} + 9 = 9 x + 13

x = - 1, x = - \frac{4}{5}

Decimal Notation

x = - 1, x = - 0.8

Solution steps

- 5 x^{2} + 9 = 9 x + 13

Move

13

to the left side

- 5 x^{2} - 4 = 9 x

Move

9 x

to the left side

- 5 x^{2} - 4 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} - 9 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 5 ) ( - 4 )}{2 ( - 5 )}

(- 9)^{2} - 4 (- 5) (- 4) = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 ( - 5 )}, x_{2} = \frac{- ( - 9 ) - 1}{2 ( - 5 )}

x = \frac{- ( - 9 ) + 1}{2 ( - 5 )} : - 1

x = \frac{- ( - 9 ) - 1}{2 ( - 5 )} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{4}{5}

\frac{r - 4}{r - 1} \geq 0

\frac{2 x + 5}{3} \geq \frac{3 x - 1}{2}

(- \frac{x}{4 - x ^{2}})^{2}

3 \cdot 3

4 x - 9 = 15

What are the solutions to the equation -5x^2+9=9x+13 ?
The solutions to the equation -5x^2+9=9x+13 are x=-1,x=-4/5
Find the zeros of -5x^2+9=9x+13
The zeros of -5x^2+9=9x+13 are x=-1,x=-4/5