What are the solutions to the equation (2x-1)^2=0 ?

The solutions to the equation (2x-1)^2=0 are x= 1/2

Find the zeros of (2x-1)^2=0

The zeros of (2x-1)^2=0 are x= 1/2

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(2 x - 1)^{2} = 0

x = \frac{1}{2}

Solution steps

(2 x - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

5 (x - 3)^{2} - 6 = 74

1 - y = 6

\frac{a ^{2}}{4} - b^{6}

\frac{6 !}{( 6 - 3 ) !}

49 p^{2} + 63 pq - 36 q^{2}

What are the solutions to the equation (2x-1)^2=0 ?
The solutions to the equation (2x-1)^2=0 are x= 1/2
Find the zeros of (2x-1)^2=0
The zeros of (2x-1)^2=0 are x= 1/2