What are the solutions to the equation x^2-12x-13=0 ?

The solutions to the equation x^2-12x-13=0 are x=13,x=-1

Find the zeros of x^2-12x-13=0

The zeros of x^2-12x-13=0 are x=13,x=-1

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x^{2} - 12 x - 13 = 0

x = 13, x = - 1

Solution steps

x^{2} - 12 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 13) = 14

x_{1, 2} = \frac{- ( - 12 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 14}{2 \cdot 1}

x = \frac{- ( - 12 ) + 14}{2 \cdot 1} : 13

x = \frac{- ( - 12 ) - 14}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 13, x = - 1

6 x^{2} + x y - 12 y^{2}

2 x^{2} - (x - 2 y) (2 x + y)

- x - 8 = 0

6^{1}

x \cdot 3 \cdot 41 = 984

What are the solutions to the equation x^2-12x-13=0 ?
The solutions to the equation x^2-12x-13=0 are x=13,x=-1
Find the zeros of x^2-12x-13=0
The zeros of x^2-12x-13=0 are x=13,x=-1