What are the solutions to the equation (x-8)(x+4)=0 ?

The solutions to the equation (x-8)(x+4)=0 are x=8,x=-4

Find the zeros of (x-8)(x+4)=0

The zeros of (x-8)(x+4)=0 are x=8,x=-4

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(x - 8) (x + 4) = 0

x = 8, x = - 4

Solution steps

(x - 8) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 8 = 0 or x + 4 = 0

Solve

x - 8 = 0 : x = 8

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = 8, x = - 4

x^{3} - 3 x^{2} - 13 x + 15 > 0

(- 1)^{4}

(\frac{x}{4})^{3}

- 5 x^{2} - 14 x + 3

9 v^{2} - 30 v = - 25

What are the solutions to the equation (x-8)(x+4)=0 ?
The solutions to the equation (x-8)(x+4)=0 are x=8,x=-4
Find the zeros of (x-8)(x+4)=0
The zeros of (x-8)(x+4)=0 are x=8,x=-4