What are the solutions to the equation x^2+1=2 ?

The solutions to the equation x^2+1=2 are x=1,x=-1

Find the zeros of x^2+1=2

The zeros of x^2+1=2 are x=1,x=-1

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x^{2} + 1 = 2

x = 1, x = - 1

Solution steps

x^{2} + 1 = 2

Move

1

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

x - 500 = (x - 600) 1.5

\frac{25}{128}

1 6^{\frac{5}{2}}

\frac{5}{x - 2} \leq \frac{4}{x - 1}

x^{3} + 5 x^{2} - 2 x - 24

What are the solutions to the equation x^2+1=2 ?
The solutions to the equation x^2+1=2 are x=1,x=-1
Find the zeros of x^2+1=2
The zeros of x^2+1=2 are x=1,x=-1