What are the solutions to the equation f^2+4f+4=0 ?

The solutions to the equation f^2+4f+4=0 are f=-2

Find the zeros of f^2+4f+4=0

The zeros of f^2+4f+4=0 are f=-2

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f^{2} + 4 f + 4 = 0

f = - 2

Solution steps

f^{2} + 4 f + 4 = 0

Solve with the quadratic formula

f_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

f_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

f = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

f = - 2

The solution to the quadratic equation is:

f = - 2

- 23 x - 14 = 14 x - 23

7 x - 2 = 2 x + 1

2 a^{2} - 46 a + 252 = 0

4 x^{2} + 8 x - 5 = 0

1 7^{2} = 1 5^{2} + x^{2}

What are the solutions to the equation f^2+4f+4=0 ?
The solutions to the equation f^2+4f+4=0 are f=-2
Find the zeros of f^2+4f+4=0
The zeros of f^2+4f+4=0 are f=-2