What are the solutions to the equation 0=-3/50 (x-20)^2+24 ?

The solutions to the equation 0=-3/50 (x-20)^2+24 are x=40,x=0

Find the zeros of 0=-3/50 (x-20)^2+24

The zeros of 0=-3/50 (x-20)^2+24 are x=40,x=0

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0 = - \frac{3}{50} (x - 20)^{2} + 24

x = 40, x = 0

Solution steps

0 = - \frac{3}{50} (x - 20)^{2} + 24

Switch sides

- \frac{3}{50} (x - 20)^{2} + 24 = 0

Move

24

to the right side

- \frac{3}{50} (x - 20)^{2} = - 24

Multiply both sides by

50

- 3 (x - 20)^{2} = - 1200

Divide both sides by

- 3

(x - 20)^{2} = 400

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 20 = 400 : x = 40

Solve

x - 20 = - 400 : x = 0

The solutions to the quadratic equation are:

x = 40, x = 0

- 5 \frac{- x + 4}{5} > 11 - 3 x

50 \cdot (1 - e^{\frac{- 4}{8 \cdot 6}})

8 - 50 x^{4}

\frac{2 x ^{3} y ^{5}}{5 ( x ^{4} y ^{2} ) ^{3}}

x^{2} + 6 x \leq 0

What are the solutions to the equation 0=-3/50 (x-20)^2+24 ?
The solutions to the equation 0=-3/50 (x-20)^2+24 are x=40,x=0
Find the zeros of 0=-3/50 (x-20)^2+24
The zeros of 0=-3/50 (x-20)^2+24 are x=40,x=0