What is factor t^2+t+1/4 ?

The solution to factor t^2+t+1/4 is (t+1/2)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor t^2+t+1/4

factor

t^{2} + t + \frac{1}{4}

(t + \frac{1}{2})^{2}

Solution steps

t^{2} + t + \frac{1}{4}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

\frac{1}{4} = (\frac{1}{2})^{2}

t = 2 t \frac{1}{2}

= t^{2} + 2 t \frac{1}{2} + (\frac{1}{2})^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

t^{2} + 2 t \frac{1}{2} + (\frac{1}{2})^{2} = (t + \frac{1}{2})^{2}

= (t + \frac{1}{2})^{2}

x^{2} + 14 x + 42 = 0

\frac{19 m + 3 m ^{3}}{14 m - 3} - \frac{12 m ^{2} + 3 m}{14 m - 3}

49 a^{2} - 14 a + 1

∣ x - 2 ∣ - 5 \leq - 2

(\frac{1}{27})^{- \frac{2}{3}}