What are the solutions to the equation 4x^2+4x=0 ?

The solutions to the equation 4x^2+4x=0 are x=0,x=-1

Find the zeros of 4x^2+4x=0

The zeros of 4x^2+4x=0 are x=0,x=-1

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4 x^{2} + 4 x = 0

x = 0, x = - 1

Solution steps

4 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 4}, x_{2} = \frac{- 4 - 4}{2 \cdot 4}

x = \frac{- 4 + 4}{2 \cdot 4} : 0

x = \frac{- 4 - 4}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

- 18 x^{2} - 39 x - 21

- 2 - 6 i

5 x - 4 (- 10) = 20

\frac{1}{6} + \frac{2}{4}

What are the solutions to the equation 4x^2+4x=0 ?
The solutions to the equation 4x^2+4x=0 are x=0,x=-1
Find the zeros of 4x^2+4x=0
The zeros of 4x^2+4x=0 are x=0,x=-1