What are the solutions to the equation x^2-14x+3=0 ?

The solutions to the equation x^2-14x+3=0 are x=7+sqrt(46),x=7-sqrt(46)

Find the zeros of x^2-14x+3=0

The zeros of x^2-14x+3=0 are x=7+sqrt(46),x=7-sqrt(46)

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x^{2} - 14 x + 3 = 0

x = 7 + 46, x = 7 - 46

Decimal Notation

x = 13.78232 \dots, x = 0.21767 \dots

Solution steps

x^{2} - 14 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 3 = 246

x_{1, 2} = \frac{- ( - 14 ) \pm 2 46}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 46}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 46}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 46}{2 \cdot 1} : 7 + 46

x = \frac{- ( - 14 ) - 2 46}{2 \cdot 1} : 7 - 46

The solutions to the quadratic equation are:

x = 7 + 46, x = 7 - 46

(x^{2} + 4) (x^{2} + 4 x) > 0

\frac{( \frac{π}{2} ) ^{2}}{2}

- 2 \cdot \frac{1}{3}

- \frac{4}{2 ^{5}}

4 x^{3} - 7 x^{2} \geq 2 x

What are the solutions to the equation x^2-14x+3=0 ?
The solutions to the equation x^2-14x+3=0 are x=7+sqrt(46),x=7-sqrt(46)
Find the zeros of x^2-14x+3=0
The zeros of x^2-14x+3=0 are x=7+sqrt(46),x=7-sqrt(46)