What is sqrt(9a^2b^{-4)} ?

The solution to sqrt(9a^2b^{-4)} is (3a)/(b^2)

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simplify sqrt(9a^2b^{-4)}

simplify

9 a^{2} b^{- 4}

\frac{3 a}{b ^{2}}

Solution steps

9 a^{2} b^{- 4}

9 a^{2} b^{- 4} = 9 a^{2} b^{- 4}

= 9 a^{2} b^{- 4}

9 = 3

= 3 a^{2} b^{- 4}

Apply radical rule:

a^{2} = a,

assuming

a \geq 0

a^{2} = a

= 3 a b^{- 4}

Simplify

b^{- 4} : \frac{1}{b ^{2}}

= 3 a \frac{1}{b ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 a \cdot 1}{b ^{2}}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{3 a}{b ^{2}}

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