What are the solutions to the equation 3x^2+5x-7=0 ?

The solutions to the equation 3x^2+5x-7=0 are x=(-5+sqrt(109))/6 ,x=(-5-sqrt(109))/6

Find the zeros of 3x^2+5x-7=0

The zeros of 3x^2+5x-7=0 are x=(-5+sqrt(109))/6 ,x=(-5-sqrt(109))/6

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3 x^{2} + 5 x - 7 = 0

x = \frac{- 5 + 109}{6}, x = \frac{- 5 - 109}{6}

Decimal Notation

x = 0.90671 \dots, x = - 2.57338 \dots

Solution steps

3 x^{2} + 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 7) = 109

x_{1, 2} = \frac{- 5 \pm 109}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 109}{2 \cdot 3}, x_{2} = \frac{- 5 - 109}{2 \cdot 3}

x = \frac{- 5 + 109}{2 \cdot 3} : \frac{- 5 + 109}{6}

x = \frac{- 5 - 109}{2 \cdot 3} : \frac{- 5 - 109}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 109}{6}, x = \frac{- 5 - 109}{6}

\frac{5}{10} + \frac{3}{2}

3 6^{- \frac{1}{2}}

3 n^{2} - 30 n + 75

\frac{1}{3} - 1

5 - \frac{4}{5}

What are the solutions to the equation 3x^2+5x-7=0 ?
The solutions to the equation 3x^2+5x-7=0 are x=(-5+sqrt(109))/6 ,x=(-5-sqrt(109))/6
Find the zeros of 3x^2+5x-7=0
The zeros of 3x^2+5x-7=0 are x=(-5+sqrt(109))/6 ,x=(-5-sqrt(109))/6