What are the solutions to the equation x^2+6x=10 ?

The solutions to the equation x^2+6x=10 are x=-3+sqrt(19),x=-3-sqrt(19)

Find the zeros of x^2+6x=10

The zeros of x^2+6x=10 are x=-3+sqrt(19),x=-3-sqrt(19)

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x^{2} + 6 x = 10

x = - 3 + 19, x = - 3 - 19

Decimal Notation

x = 1.35889 \dots, x = - 7.35889 \dots

Solution steps

x^{2} + 6 x = 10

Move

10

to the left side

x^{2} + 6 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 10) = 219

x_{1, 2} = \frac{- 6 \pm 2 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 19}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 19}{2 \cdot 1}

x = \frac{- 6 + 2 19}{2 \cdot 1} : - 3 + 19

x = \frac{- 6 - 2 19}{2 \cdot 1} : - 3 - 19

The solutions to the quadratic equation are:

x = - 3 + 19, x = - 3 - 19

6 x^{2} - 7 x - 3 = 0

\frac{3 x + 5}{2} - \frac{4 x - 5}{3} = \frac{7 x + 1}{6} - 5

8 g > 16

3 x - 1 = 14

∣ 2 x - 3 ∣ > 5

What are the solutions to the equation x^2+6x=10 ?
The solutions to the equation x^2+6x=10 are x=-3+sqrt(19),x=-3-sqrt(19)
Find the zeros of x^2+6x=10
The zeros of x^2+6x=10 are x=-3+sqrt(19),x=-3-sqrt(19)