What is factor a^6-64 ?

The solution to factor a^6-64 is (a+2)(a-2)(a^2+4+2a)(a^2+4-2a)

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factor a^6-64

factor

a^{6} - 64

(a + 2) (a - 2) (a^{2} + 4 + 2 a) (a^{2} + 4 - 2 a)

Solution steps

a^{6} - 64

Apply exponent rules

= (a^{2})^{3} - 4^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(a^{2})^{3} - 4^{3} = (a^{2} - 4) (a^{4} + 4 a^{2} + 4^{2})

= (a^{2} - 4) (a^{4} + 4 a^{2} + 4^{2})

Factor

a^{2} - 4 : (a + 2) (a - 2)

= (a + 2) (a - 2) (a^{4} + 4 a^{2} + 4^{2})

Factor

a^{4} + 4 a^{2} + 4^{2} : (a^{2} + 4 + 2 a) (a^{2} + 4 - 2 a)

= (a + 2) (a - 2) (a^{2} + 4 + 2 a) (a^{2} + 4 - 2 a)

∣ 1 - 5 x ∣ + 2 \geq 9

\frac{13 !}{5 !}

\frac{x}{4} = \frac{5}{6}

- 12 \geq 24 x

What is factor a^6-64 ?
The solution to factor a^6-64 is (a+2)(a-2)(a^2+4+2a)(a^2+4-2a)