What are the solutions to the equation x^2+18x+129=0 ?

The solutions to the equation x^2+18x+129=0 are x=-9+4sqrt(3)i,x=-9-4sqrt(3)i

Find the zeros of x^2+18x+129=0

The zeros of x^2+18x+129=0 are x=-9+4sqrt(3)i,x=-9-4sqrt(3)i

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x^{2} + 18 x + 129 = 0

x = - 9 + 43 i, x = - 9 - 43 i

Solution steps

x^{2} + 18 x + 129 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 129}{2 \cdot 1}

Simplify

1 8^{2} - 4 \cdot 1 \cdot 129 : 83 i

x_{1, 2} = \frac{- 18 \pm 8 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 8 3 i}{2 \cdot 1}, x_{2} = \frac{- 18 - 8 3 i}{2 \cdot 1}

x = \frac{- 18 + 8 3 i}{2 \cdot 1} : - 9 + 43 i

x = \frac{- 18 - 8 3 i}{2 \cdot 1} : - 9 - 43 i

The solutions to the quadratic equation are:

x = - 9 + 43 i, x = - 9 - 43 i

2 x + 11 = - 2 x - 8

\frac{3}{4} y - 11 \leq \frac{6}{5} + 12 y

1.75 \cdot 1 0^{- 5} = \frac{x ^{2}}{0.1}

- 2 = \frac{a ( 0 - 3 )}{( 0 + 3 ) ( 0 - 4 )}

9 m^{2} - 25 n^{2}

What are the solutions to the equation x^2+18x+129=0 ?
The solutions to the equation x^2+18x+129=0 are x=-9+4sqrt(3)i,x=-9-4sqrt(3)i
Find the zeros of x^2+18x+129=0
The zeros of x^2+18x+129=0 are x=-9+4sqrt(3)i,x=-9-4sqrt(3)i