What are the solutions to the equation v^2+9v+14=0 ?

The solutions to the equation v^2+9v+14=0 are v=-2,v=-7

Find the zeros of v^2+9v+14=0

The zeros of v^2+9v+14=0 are v=-2,v=-7

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v^{2} + 9 v + 14 = 0

v = - 2, v = - 7

Solution steps

v^{2} + 9 v + 14 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 14 = 5

v_{1, 2} = \frac{- 9 \pm 5}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 9 + 5}{2 \cdot 1}, v_{2} = \frac{- 9 - 5}{2 \cdot 1}

v = \frac{- 9 + 5}{2 \cdot 1} : - 2

v = \frac{- 9 - 5}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

v = - 2, v = - 7

- 2 < 2 x + 1 < 7

- 8 x \geq 24

y (y - 6) + 9 (y - 6)

2 (4 x - 1) = 8 x - 2

- 3 x - 4 < 5

What are the solutions to the equation v^2+9v+14=0 ?
The solutions to the equation v^2+9v+14=0 are v=-2,v=-7
Find the zeros of v^2+9v+14=0
The zeros of v^2+9v+14=0 are v=-2,v=-7