What are the solutions to the equation -3x^2+6x+9=0 ?

The solutions to the equation -3x^2+6x+9=0 are x=-1,x=3

Find the zeros of -3x^2+6x+9=0

The zeros of -3x^2+6x+9=0 are x=-1,x=3

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- 3 x^{2} + 6 x + 9 = 0

x = - 1, x = 3

Solution steps

- 3 x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 9}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 9 = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 ( - 3 )}, x_{2} = \frac{- 6 - 12}{2 ( - 3 )}

x = \frac{- 6 + 12}{2 ( - 3 )} : - 1

x = \frac{- 6 - 12}{2 ( - 3 )} : 3

The solutions to the quadratic equation are:

x = - 1, x = 3

24 3^{- \frac{3}{5}}

\frac{x ^{3} - x}{x ^{2} + 1} > 0

5 x - 3 = 3 x + 5

7 n + 2 = 4 n + 17

2 x^{2} - 20 x + 42

What are the solutions to the equation -3x^2+6x+9=0 ?
The solutions to the equation -3x^2+6x+9=0 are x=-1,x=3
Find the zeros of -3x^2+6x+9=0
The zeros of -3x^2+6x+9=0 are x=-1,x=3