What are the solutions to the equation (z-4)^2+25=0 ?

The solutions to the equation (z-4)^2+25=0 are z=5i+4,z=-5i+4

Find the zeros of (z-4)^2+25=0

The zeros of (z-4)^2+25=0 are z=5i+4,z=-5i+4

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(z - 4)^{2} + 25 = 0

z = 5 i + 4, z = - 5 i + 4

Solution steps

(z - 4)^{2} + 25 = 0

Move

25

to the right side

(z - 4)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z - 4 = - 25 : z = 5 i + 4

Solve

z - 4 = - - 25 : z = - 5 i + 4

The solutions to the quadratic equation are:

z = 5 i + 4, z = - 5 i + 4

\frac{5}{2} (- 4)

\frac{3 + 4 i}{1 - 2 i}

2 x^{2} - 2 x + 3 = 0

3 (4 k - \frac{1}{3}) = 12 k - 1

\frac{6}{10} \cdot \frac{4}{9}

What are the solutions to the equation (z-4)^2+25=0 ?
The solutions to the equation (z-4)^2+25=0 are z=5i+4,z=-5i+4
Find the zeros of (z-4)^2+25=0
The zeros of (z-4)^2+25=0 are z=5i+4,z=-5i+4