What are the solutions to the equation x^2=-32 ?

The solutions to the equation x^2=-32 are x=4sqrt(2)i,x=-4sqrt(2)i

Find the zeros of x^2=-32

The zeros of x^2=-32 are x=4sqrt(2)i,x=-4sqrt(2)i

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x^{2} = - 32

x = 42 i, x = - 42 i

Solution steps

x^{2} = - 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 32, x = - - 32

- 32 = 42 i

- - 32 = - 42 i

x = 42 i, x = - 42 i

8 - ∣ 2 x - 3 ∣ = 5

(x^{- 5} y^{\frac{1}{3}})^{- \frac{3}{5}}

2 (3 w + 8) = 40

x^{2} + 16 x + 15

- 4 s + 5 (10 s + 3) > 4 s - 9 - 9

What are the solutions to the equation x^2=-32 ?
The solutions to the equation x^2=-32 are x=4sqrt(2)i,x=-4sqrt(2)i
Find the zeros of x^2=-32
The zeros of x^2=-32 are x=4sqrt(2)i,x=-4sqrt(2)i