What is factor 3(z-4)^2+9(z-4)^3 ?

The solution to factor 3(z-4)^2+9(z-4)^3 is 3(z-4)^2(3z-11)

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factor 3(z-4)^2+9(z-4)^3

factor

3 (z - 4)^{2} + 9 (z - 4)^{3}

3 (z - 4)^{2} (3 z - 11)

Solution steps

3 (z - 4)^{2} + 9 (z - 4)^{3}

Factor out common term

3 (z - 4)^{2} : 3 (z - 4)^{2} (1 + 3 (z - 4))

= 3 (z - 4)^{2} (1 + 3 (z - 4))

Expand

1 + 3 (z - 4) : 3 z - 11

= 3 (z - 4)^{2} (3 z - 11)

(x^{- 3} \cdot y^{3})^{- 7}

\frac{3 uv - 12 u w}{3 u}

x (1 - x^{2})^{3} > 7 (1 - x^{2})^{3}

\frac{x ^{5} y ^{2}}{x ^{4} y ^{0}}

x^{2} - 9 x + 14

What is factor 3(z-4)^2+9(z-4)^3 ?
The solution to factor 3(z-4)^2+9(z-4)^3 is 3(z-4)^2(3z-11)