What are the solutions to the equation 7x^2+49=0 ?

The solutions to the equation 7x^2+49=0 are x=sqrt(7)i,x=-sqrt(7)i

Find the zeros of 7x^2+49=0

The zeros of 7x^2+49=0 are x=sqrt(7)i,x=-sqrt(7)i

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7 x^{2} + 49 = 0

x = 7 i, x = - 7 i

Solution steps

7 x^{2} + 49 = 0

Move

49

to the right side

7 x^{2} = - 49

Divide both sides by

7

x^{2} = - 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 7, x = - - 7

- 7 = 7 i

- - 7 = - 7 i

x = 7 i, x = - 7 i

20 x^{2} - 11 x - 42

6^{- 5}

8 m - 6

- 4 + 15

x^{2} - 1 + x^{2} - 16 = 2

What are the solutions to the equation 7x^2+49=0 ?
The solutions to the equation 7x^2+49=0 are x=sqrt(7)i,x=-sqrt(7)i
Find the zeros of 7x^2+49=0
The zeros of 7x^2+49=0 are x=sqrt(7)i,x=-sqrt(7)i