What are the solutions to the equation x^{(2)}-4x=21 ?

The solutions to the equation x^{(2)}-4x=21 are x=7,x=-3

Find the zeros of x^{(2)}-4x=21

The zeros of x^{(2)}-4x=21 are x=7,x=-3

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x^{(2)} - 4 x = 21

x = 7, x = - 3

Solution steps

x^{(2)} - 4 x = 21

Refine

x^{2} - 4 x = 21

Move

21

to the left side

x^{2} - 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 1}

x = \frac{- ( - 4 ) + 10}{2 \cdot 1} : 7

x = \frac{- ( - 4 ) - 10}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 7, x = - 3

\frac{8}{- 12 i}

4 (x + 1) - 7 = 3 (x - 1) + x

a^{2} + 8 a - 48

25 x^{2} - 121

(x - 4) (x + 1) = 0

What are the solutions to the equation x^{(2)}-4x=21 ?
The solutions to the equation x^{(2)}-4x=21 are x=7,x=-3
Find the zeros of x^{(2)}-4x=21
The zeros of x^{(2)}-4x=21 are x=7,x=-3