What are the solutions to the equation y^2+5y+6=0 ?

The solutions to the equation y^2+5y+6=0 are y=-2,y=-3

Find the zeros of y^2+5y+6=0

The zeros of y^2+5y+6=0 are y=-2,y=-3

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y^{2} + 5 y + 6 = 0

y = - 2, y = - 3

Solution steps

y^{2} + 5 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

y_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 5 + 1}{2 \cdot 1}, y_{2} = \frac{- 5 - 1}{2 \cdot 1}

y = \frac{- 5 + 1}{2 \cdot 1} : - 2

y = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

y = - 2, y = - 3

7 < 2 x + 1 \leq x + 7

384

0 = x^{2} - 25

11.4 - p \geq - 2.6

What are the solutions to the equation y^2+5y+6=0 ?
The solutions to the equation y^2+5y+6=0 are y=-2,y=-3
Find the zeros of y^2+5y+6=0
The zeros of y^2+5y+6=0 are y=-2,y=-3