What are the solutions to the equation (x^2)/2+5/2 x=2 ?

The solutions to the equation (x^2)/2+5/2 x=2 are x=(-5+sqrt(41))/2 ,x=(-5-sqrt(41))/2

Find the zeros of (x^2)/2+5/2 x=2

The zeros of (x^2)/2+5/2 x=2 are x=(-5+sqrt(41))/2 ,x=(-5-sqrt(41))/2

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\frac{x ^{2}}{2} + \frac{5}{2} x = 2

x = \frac{- 5 + 41}{2}, x = \frac{- 5 - 41}{2}

Decimal Notation

x = 0.70156 \dots, x = - 5.70156 \dots

Solution steps

\frac{x ^{2}}{2} + \frac{5}{2} x = 2

Multiply both sides by

2

x^{2} + 5 x = 4

Move

4

to the left side

x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 4) = 41

x_{1, 2} = \frac{- 5 \pm 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 41}{2 \cdot 1}, x_{2} = \frac{- 5 - 41}{2 \cdot 1}

x = \frac{- 5 + 41}{2 \cdot 1} : \frac{- 5 + 41}{2}

x = \frac{- 5 - 41}{2 \cdot 1} : \frac{- 5 - 41}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 41}{2}, x = \frac{- 5 - 41}{2}

16 a^{2} - 49

- 35 - 7 n < - 4 (- 4 + 6 n)

27 (312 + 58)

a (a + 1) - (a + 1)^{2}

- \frac{2}{8}

What are the solutions to the equation (x^2)/2+5/2 x=2 ?
The solutions to the equation (x^2)/2+5/2 x=2 are x=(-5+sqrt(41))/2 ,x=(-5-sqrt(41))/2
Find the zeros of (x^2)/2+5/2 x=2
The zeros of (x^2)/2+5/2 x=2 are x=(-5+sqrt(41))/2 ,x=(-5-sqrt(41))/2