What is |3x-5|>x^2-3x ?

The solution to |3x-5|>x^2-3x is -sqrt(5)<x<5

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|3x-5|>x^2-3x

∣ 3 x - 5 ∣ > x^{2} - 3 x

- 5 < x < 5

Interval Notation

(- 5, 5)

Decimal Notation

- 2.23606 \dots < x < 5

Solution steps

∣ 3 x - 5 ∣ > x^{2} - 3 x

Find positive and negative intervals

x < \frac{5}{3}, x \geq \frac{5}{3}

Solve the inequality for each interval

- 5 < x < \frac{5}{3} or \frac{5}{3} \leq x < 5

Merge Overlapping Intervals

- 5 < x < 5

m^{2} + 10 m + 9

2 x + x + x + 2 y \times 3 y \times y

5 \cdot 12

4 x - 2 \leq - 22

x + 2 > 4