What are the solutions to the equation -2x^2=-162 ?

The solutions to the equation -2x^2=-162 are x=9,x=-9

Find the zeros of -2x^2=-162

The zeros of -2x^2=-162 are x=9,x=-9

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- 2 x^{2} = - 162

x = 9, x = - 9

Solution steps

- 2 x^{2} = - 162

Divide both sides by

- 2

x^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

1.6 x + x^{2} = 0

x^{2} + \frac{12}{11} x + \frac{35}{121} = 0

3 x^{2} - 4 x + 11 = 0

10 x^{2} + 29 x - 21

m^{- 2} \cdot n^{3}

What are the solutions to the equation -2x^2=-162 ?
The solutions to the equation -2x^2=-162 are x=9,x=-9
Find the zeros of -2x^2=-162
The zeros of -2x^2=-162 are x=9,x=-9