What are the solutions to the equation 5x^2+6x-3=0 ?

The solutions to the equation 5x^2+6x-3=0 are x=(-3+2sqrt(6))/5 ,x=-(3+2sqrt(6))/5

Find the zeros of 5x^2+6x-3=0

The zeros of 5x^2+6x-3=0 are x=(-3+2sqrt(6))/5 ,x=-(3+2sqrt(6))/5

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5 x^{2} + 6 x - 3 = 0

x = \frac{- 3 + 2 6}{5}, x = - \frac{3 + 2 6}{5}

Decimal Notation

x = 0.37979 \dots, x = - 1.57979 \dots

Solution steps

5 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 3) = 46

x_{1, 2} = \frac{- 6 \pm 4 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 4 6}{2 \cdot 5}, x_{2} = \frac{- 6 - 4 6}{2 \cdot 5}

x = \frac{- 6 + 4 6}{2 \cdot 5} : \frac{- 3 + 2 6}{5}

x = \frac{- 6 - 4 6}{2 \cdot 5} : - \frac{3 + 2 6}{5}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2 6}{5}, x = - \frac{3 + 2 6}{5}

8 - 2

\frac{6}{7} - \frac{2}{3}

\frac{6 n + 6 i}{2 n}

- 16 t^{2} + 70 t + 5 = 40

x^{3} - 8 x^{2} - x + 8 \geq 0

What are the solutions to the equation 5x^2+6x-3=0 ?
The solutions to the equation 5x^2+6x-3=0 are x=(-3+2sqrt(6))/5 ,x=-(3+2sqrt(6))/5
Find the zeros of 5x^2+6x-3=0
The zeros of 5x^2+6x-3=0 are x=(-3+2sqrt(6))/5 ,x=-(3+2sqrt(6))/5