What is (1-2x)/3-1/3 <2-(2x)/3 <-(x-1)/3 ?

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(1-2x)/3-1/3 <2-(2x)/3 <-(x-1)/3

\frac{1 - 2 x}{3} - \frac{1}{3} < 2 - \frac{2 x}{3} < - \frac{x - 1}{3}

x > 5

Interval Notation

(5, \infty)

Solution steps

\frac{1 - 2 x}{3} - \frac{1}{3} < 2 - \frac{2 x}{3} < - \frac{x - 1}{3}

a < u < b

then

a < u and u < b

\frac{1 - 2 x}{3} - \frac{1}{3} < 2 - \frac{2 x}{3} and 2 - \frac{2 x}{3} < - \frac{x - 1}{3}

\frac{1 - 2 x}{3} - \frac{1}{3} < 2 - \frac{2 x}{3} :

True for all

x

2 - \frac{2 x}{3} < - \frac{x - 1}{3} : x > 5

Combine the intervals

True for all x and x > 5

Merge Overlapping Intervals

x > 5

\frac{x}{5} - 1 = \frac{x}{5}

4 x^{2} + 14 x + 84 = 0

- 5.8 c + 4.2 - 3.1 + 1.4 c

- 60 = - 24 + 12 r

\frac{- 11 s - 4}{8} = 5

What is (1-2x)/3-1/3 <2-(2x)/3 <-(x-1)/3 ?
The solution to (1-2x)/3-1/3 <2-(2x)/3 <-(x-1)/3 is x>5