What are the solutions to the equation x(x+4)=-20 ?

The solutions to the equation x(x+4)=-20 are x=-2+4i,x=-2-4i

Find the zeros of x(x+4)=-20

The zeros of x(x+4)=-20 are x=-2+4i,x=-2-4i

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x (x + 4) = - 20

x = - 2 + 4 i, x = - 2 - 4 i

Solution steps

x (x + 4) = - 20

Expand

x (x + 4) : x^{2} + 4 x

x^{2} + 4 x = - 20

Move

20

to the left side

x^{2} + 4 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 20 : 8 i

x_{1, 2} = \frac{- 4 \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 8 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 8 i}{2 \cdot 1}

x = \frac{- 4 + 8 i}{2 \cdot 1} : - 2 + 4 i

x = \frac{- 4 - 8 i}{2 \cdot 1} : - 2 - 4 i

The solutions to the quadratic equation are:

x = - 2 + 4 i, x = - 2 - 4 i

(5 + 3) j = 48

- 3 x^{2} + 18 x = 0

- \frac{24}{( 4 ( - 1 ) + 1 ) ^{2}}

∣ x ∣ = x^{2} - 1

x + x^{2} = 20

What are the solutions to the equation x(x+4)=-20 ?
The solutions to the equation x(x+4)=-20 are x=-2+4i,x=-2-4i
Find the zeros of x(x+4)=-20
The zeros of x(x+4)=-20 are x=-2+4i,x=-2-4i