What are the solutions to the equation y^2+7y-2=0 ?

The solutions to the equation y^2+7y-2=0 are y=(-7+sqrt(57))/2 ,y=(-7-sqrt(57))/2

Find the zeros of y^2+7y-2=0

The zeros of y^2+7y-2=0 are y=(-7+sqrt(57))/2 ,y=(-7-sqrt(57))/2

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y^{2} + 7 y - 2 = 0

y = \frac{- 7 + 57}{2}, y = \frac{- 7 - 57}{2}

Decimal Notation

y = 0.27491 \dots, y = - 7.27491 \dots

Solution steps

y^{2} + 7 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 2) = 57

y_{1, 2} = \frac{- 7 \pm 57}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 7 + 57}{2 \cdot 1}, y_{2} = \frac{- 7 - 57}{2 \cdot 1}

y = \frac{- 7 + 57}{2 \cdot 1} : \frac{- 7 + 57}{2}

y = \frac{- 7 - 57}{2 \cdot 1} : \frac{- 7 - 57}{2}

The solutions to the quadratic equation are:

y = \frac{- 7 + 57}{2}, y = \frac{- 7 - 57}{2}

7 x^{2} - x - 8

(a^{\frac{1}{2}} - b^{- \frac{1}{2}})^{2}

a^{3} b - a b^{3}

r^{2} - 2 r - 8

- 3 (x + 12) = x^{6} - (1 - x)

What are the solutions to the equation y^2+7y-2=0 ?
The solutions to the equation y^2+7y-2=0 are y=(-7+sqrt(57))/2 ,y=(-7-sqrt(57))/2
Find the zeros of y^2+7y-2=0
The zeros of y^2+7y-2=0 are y=(-7+sqrt(57))/2 ,y=(-7-sqrt(57))/2