What are the solutions to the equation w^2-9w+20=0 ?

The solutions to the equation w^2-9w+20=0 are w=5,w=4

Find the zeros of w^2-9w+20=0

The zeros of w^2-9w+20=0 are w=5,w=4

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w^{2} - 9 w + 20 = 0

w = 5, w = 4

Solution steps

w^{2} - 9 w + 20 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

w_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, w_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

w = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

w = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

w = 5, w = 4

7 x + 2 \leq 16

x^{3} - 3 x^{2} - 3 x + 1

∣ 35 x - 15 ∣ + 15 = - 15

a = 2 a (1 - a)

e^{\frac{πi}{2}}

What are the solutions to the equation w^2-9w+20=0 ?
The solutions to the equation w^2-9w+20=0 are w=5,w=4
Find the zeros of w^2-9w+20=0
The zeros of w^2-9w+20=0 are w=5,w=4