What are the solutions to the equation z^2+5/2 z+1=0 ?

The solutions to the equation z^2+5/2 z+1=0 are z=-1/2 ,z=-2

Find the zeros of z^2+5/2 z+1=0

The zeros of z^2+5/2 z+1=0 are z=-1/2 ,z=-2

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z^{2} + \frac{5}{2} z + 1 = 0

z = - \frac{1}{2}, z = - 2

Solution steps

z^{2} + \frac{5}{2} z + 1 = 0

Multiply both sides by

2

2 z^{2} + 5 z + 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 2 = 3

z_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- 5 + 3}{2 \cdot 2}, z_{2} = \frac{- 5 - 3}{2 \cdot 2}

z = \frac{- 5 + 3}{2 \cdot 2} : - \frac{1}{2}

z = \frac{- 5 - 3}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

z = - \frac{1}{2}, z = - 2

i^{32}

7 n = 2 n - 5 (- 5)

- 5 (x - 4) + 2 = - 1 + (x + 6)

3 x - 6 = 21

- 9 \leq \frac{2 x + 3}{- 4} \leq 7

What are the solutions to the equation z^2+5/2 z+1=0 ?
The solutions to the equation z^2+5/2 z+1=0 are z=-1/2 ,z=-2
Find the zeros of z^2+5/2 z+1=0
The zeros of z^2+5/2 z+1=0 are z=-1/2 ,z=-2