What is factor 4n^{12}-32n^7+48n^2 ?

The solution to factor 4n^{12}-32n^7+48n^2 is 4n^2(n^{10}-8n^5+12)

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factor 4n^{12}-32n^7+48n^2

factor

4 n^{12} - 32 n^{7} + 48 n^{2}

4 n^{2} (n^{10} - 8 n^{5} + 12)

Solution steps

4 n^{12} - 32 n^{7} + 48 n^{2}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

n^{7} = n^{5} n^{2}

= 4 n^{10} n^{2} - 32 n^{5} n^{2} + 48 n^{2}

Rewrite

32

4 \cdot 8

Rewrite

48

4 \cdot 12

= 4 n^{10} n^{2} - 4 \cdot 8 n^{5} n^{2} + 4 \cdot 12 n^{2}

Factor out common term

4 n^{2}

= 4 n^{2} (n^{10} - 8 n^{5} + 12)

\frac{2}{32}

- 4 x \geq 10

121 b^{4} - 49

3 x^{2} - 4 x = 2

15 x - 20 x y

What is factor 4n^{12}-32n^7+48n^2 ?
The solution to factor 4n^{12}-32n^7+48n^2 is 4n^2(n^{10}-8n^5+12)